6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
How to prove that sin 780 sin 480 + cos 120 sin 30=1/2 - Quora
What is the value of sin150? - Quora
Trigonometric Functions of Any Angle - Trigonometry
cos^(-1) sin (-60^(@))`
How to prove that sin 780 sin 480 + cos 120 sin 30=1/2 - Quora
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Ex 8.2, 1 Class 10 - Evaluate (i) sin 60° cos 30° + sin 30° cos 60°
Show that : `(i) (1-sin60^(@))/(cos60^(@))=(tan60^(@)-1)/(tan60^(@)+1)` `(ii) (cos30^(@)+sin60^(@))/
What is the value of sin150? - Quora
What is the value of sin150? - Quora
How to prove that sin 780 sin 480 + cos 120 sin 30=1/2 - Quora
Solved e (degrees) 0° 30° 45° 60°, 90° 120° 135° 150° 180°
If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these
How to prove that sin 780 sin 480 + cos 120 sin 30=1/2 - Quora
